Learning Outcome
Turn the Google Wordle Feedback Validation interview variant into a clear brute-force baseline, optimized pattern, and implementation plan.
Original Interview Statement
Given guess1 and its color feedback, decide whether another candidate secret is consistent with that feedback.
Examples
| Item | Detail |
|---|---|
| guess1 = split, color = ybggg, candidate = adfet | false if generated feedback differs |
Brute Force Approach
Try to manually convert colors into many separate constraints; duplicate letters make this fragile.
Optimized Approach
A candidate is valid exactly when running the original feedback algorithm with candidate as secret reproduces the known color string.
Exact Pseudocode
return color(candidateSecret, guess1) == knownColor
Reference Code
def feedback(secret, guess):
from collections import Counter
ans = ['b'] * len(secret)
left = Counter()
for i, (s, g) in enumerate(zip(secret, guess)):
if s == g:
ans[i] = 'g'
else:
left[s] += 1
for i, g in enumerate(guess):
if ans[i] == 'g':
continue
if left[g] > 0:
ans[i] = 'y'
left[g] -= 1
return ''.join(ans)
def is_valid_candidate(guess1, color1, candidate_secret):
return feedback(candidate_secret, guess1) == color1Complexity
| Item | Detail |
|---|---|
| Brute force | O(26 + n) constraints but bug-prone with duplicates |
| Optimized | O(n + alphabet) time, O(alphabet) space |
Edge Cases
- Repeated letters with both yellow and black
- Green positions
- Candidate length mismatch
Follow-ups
- Validate against multiple previous guesses
- Generate any possible secret
Nearest Practice References
- Wordle
- Mastermind consistency
Common Mistakes
- Copying the nearest LeetCode solution without checking the changed rule.
- Skipping duplicate or boundary cases.
- Not stating the brute force before the optimized approach.