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Use a moving window when subarrays or substrings must remain valid under a local constraint.

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Course

DSA Interview Patterns Roadmap

Topic

Sliding Window

Learning Outcome

Use a moving window when subarrays or substrings must remain valid under a local constraint.

Pattern Recognition

ItemDetail
Core signalThe problem asks for longest, shortest, or count of contiguous ranges with a condition.
Use whenThe answer is contiguous and you can restore validity by moving the left boundary.
Avoid whenThe required invariant is not monotonic or the input constraints point to a simpler direct scan.

Intuition

The right pointer explores new data; the left pointer removes old data until the window becomes valid again.

Exact Practice Question Names

Interview Approach

  1. Expand right and update frequency state.
  2. While invalid, remove left and move left forward.
  3. Update best answer only when the window is valid.
  4. Use last-seen index optimization for no-repeat strings.

Pseudocode

left = 0
state = empty map
for right in range(n):
  add a[right] to state
  while window is invalid:
    remove a[left] from state
    left += 1
  update answer from right - left + 1

Sample Dry Run

For 'abcabcbb', the window grows to 'abc'. Seeing the next 'a' moves left after the old 'a', preserving a duplicate-free window.

Edge Cases

Common Mistakes

Complexity

ItemDetail
Expected timeO(n) because each pointer moves at most n times.
Expected spaceO(k) for the tracked alphabet or distinct values.

Java, C++ and Python Notes

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