Tree DFS and BST Inorder Patterns | DSA Interview Patterns - Study Chapter | QuizMaker

Use recursive return values, inorder sortedness, and tree-to-graph conversion for tree interview problems.

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Course

DSA Interview Patterns Roadmap

Topic

Trees and BST

Learning Outcome

Use recursive return values, inorder sortedness, and tree-to-graph conversion for tree interview problems.

Pattern Recognition

ItemDetail
Core signalThe problem asks for subtree values, path values, BST order, distance from target, or level-based properties.
Use whenEach node answer depends on left/right subtree answers or BFS levels.
Avoid whenThe required invariant is not monotonic or the input constraints point to a simpler direct scan.

Intuition

Define exactly what a recursive call returns upward; keep global answers separate when paths can bend.

Exact Practice Question Names

Interview Approach

  1. Pick traversal based on the information needed.
  2. For BST, use inorder or low/high bounds.
  3. For path sums, return one-side extendable path and update global best with a fork.
  4. For burning/distance, add parent links or build an undirected graph.

Pseudocode

dfs(node):
  if node is null: return base
  left = dfs(node.left)
  right = dfs(node.right)
  update answer using node, left, right
  return value parent needs

Sample Dry Run

In max path sum, a node may combine left + node + right for the global answer, but it can return only node plus one side to its parent.

Edge Cases

Common Mistakes

Complexity

ItemDetail
Expected timeUsually O(n).
Expected spaceO(h) recursion or O(n) for BFS/parent maps.

Java, C++ and Python Notes

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