Mixture and Alligation Made Practical | Banking Quant Mastery - Study Chapter | QuizMaker

Use weighted averages and alligation to solve value-mixing questions quickly.

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Course

Banking Quant Mastery: Arithmetic to Data Sufficiency

Topic

Module 2: Commercial Arithmetic and Value Judgement

Why This Chapter Matters

Mixture and alligation questions appear simple but hide many formats: mean price, dilution, replacement, adulteration, and ratio shifts after adding water or another liquid. Once the mean and remaining-fraction logic is clear, the whole chapter speeds up.

Core Ideas

High-Value Formulas

ConceptFormula / Rule
Mean valuemean=total valuetotal quantity\text{mean}=\frac{\text{total value}}{\text{total quantity}}mean=total quantitytotal value
Alligation ratiocheaper:dearer=(dearer−mean):(mean−cheaper)\text{cheaper} : \text{dearer}=(\text{dearer}-\text{mean}):(\text{mean}-\text{cheaper})cheaper:dearer=(dearermean):(meancheaper)
Replacement after n operationspure liquid left=x(1−yx)n\text{pure liquid left}=x\left(1-\frac{y}{x}\right)^npure liquid left=x(1xy)n

How To Approach Questions

  1. Mark the cheaper value, dearer value, and mean value.
  2. Use cross-differences for the required ratio.
  3. For replacement, multiply by the remaining fraction after each operation.
  4. If the ratio changes after adding water, first convert the old ratio into actual litres.

Worked Examples

Example 1

Prompt: Rice worth Rs 40\text{Rs }40Rs 40 per kg is mixed with rice worth Rs 60\text{Rs }60Rs 60 per kg to get a mean price of Rs 48\text{Rs }48Rs 48. Find the ratio.

Approach: Alligation gives (60−48):(48−40)=12:8=3:2(60-48):(48-40)=12:8=3:2(6048):(4840)=12:8=3:2. So the ratio of cheaper to dearer rice is 3:23:23:2.

Example 2

Prompt: A vessel contains 404040 litres of milk. If 101010 litres are removed and replaced with water, what fraction of milk remains?

Approach: Remaining milk fraction =1−1040=34=1-\frac{10}{40}=\frac34=14010=43. So milk left =40×34=30=40\times\frac34=30=40×43=30 litres.

Example 3

Prompt: A vessel contains 100100100 litres of spirit. If 101010 litres are removed and replaced with water three times, how much spirit remains?

Approach: Use the replacement formula: spirit left =100(1−10100)3=100(910)3=72.9=100\left(1-\frac{10}{100}\right)^3=100\left(\frac9{10}\right)^3=72.9=100(110010)3=100(109)3=72.9 litres.

Common Mistakes

Quick Revision

Think weighted average first, then ask whether the problem is about pricing, dilution, or repeated replacement.

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