Skip to content
QuizMaker logoQuizMaker
Activity
DSA Course: Interview Patterns and Problem Solving
Module 5: Linked List
Best Time to Buy and Sell Stock: Greedy Pattern
Maximum Subarray: Kadane Pattern
Move Zeroes: Two pointers Pattern
Contains Duplicate: Set Pattern
Valid Anagram: Frequency map Pattern
Longest Substring Without Repeating Characters: Sliding window Pattern
Valid Palindrome: Two pointers Pattern
Longest Palindromic Substring: Expand around center Pattern
Group Anagrams: Hash key Pattern
Binary Search: Classic search Pattern
Search Insert Position: Lower bound Pattern
First Bad Version: Predicate search Pattern
Search in Rotated Sorted Array: Rotated search Pattern
Find Minimum in Rotated Sorted Array: Rotated minimum Pattern
Valid Parentheses: Stack matching Pattern
Min Stack: Auxiliary stack Pattern
Daily Temperatures: Monotonic stack Pattern
Next Greater Element I: Monotonic stack Pattern
Evaluate Reverse Polish Notation: Stack evaluation Pattern
Reverse Linked List: Pointer reversal Pattern
Merge Two Sorted Lists: Dummy node Pattern
Linked List Cycle: Fast and slow pointers Pattern
Middle of the Linked List: Fast and slow pointers Pattern
Remove Nth Node From End: Two pointers Pattern
Binary Tree Traversals: DFS recursion Pattern
Maximum Depth of Binary Tree: Height recursion Pattern
Binary Tree Level Order Traversal: BFS queue Pattern
Validate Binary Search Tree: Range bounds Pattern
Lowest Common Ancestor: Recursive split Pattern
Connected Components: Adjacency DFS Pattern
Number of Islands: Grid DFS Pattern
Flood Fill: Boundary DFS Pattern
Clone Graph: Hash Map DFS Pattern
Course Schedule: Topological Sort Pattern
Union Find Components: Disjoint Set Pattern
Shortest Path in Unweighted Graph: BFS Distance Pattern
Climbing Stairs: Fibonacci DP Pattern
House Robber: Pick or Skip DP Pattern
Coin Change: Minimum Coins DP Pattern
Longest Increasing Subsequence: Binary Search DP Pattern
Longest Common Subsequence: 2D DP Pattern
0/1 Knapsack: Capacity DP Pattern
Longest Consecutive Sequence: Hash Set Pattern
Subarray Sum Equals K: Prefix Sum Hashmap Pattern
First Unique Character: Frequency Map Pattern
Find Duplicates: Frequency Map Pattern
Ransom Note: Character Availability Pattern
Sort Colors: Dutch National Flag Pattern
Next Permutation: Pivot and Suffix Reversal Pattern
Merge Intervals: Sort and Sweep Pattern
Find First and Last Position: Boundary Binary Search Pattern
Search a 2D Matrix: Flattened Binary Search Pattern
Subsets: Pick or Skip Recursion Pattern
Generate Parentheses: Valid State Backtracking Pattern
Combination Sum: Reuse Choice Backtracking Pattern
N-Queens: Constraint Backtracking Pattern
Word Search: Grid Backtracking Pattern
Kth Largest Element: Size-K Min-Heap Pattern
Top K Frequent Elements: Frequency Heap Pattern
Merge K Sorted Lists: Min-Heap Multiway Merge Pattern
Median Finder: Two Heaps Pattern
Task Scheduler: Greedy Max-Heap Pattern
Jump Game: Farthest Reach Greedy Pattern
Gas Station: Greedy Reset Pattern
Non-overlapping Intervals: Earliest End Greedy Pattern
Minimum Arrows to Burst Balloons: Interval End Greedy Pattern
Partition Labels: Last Occurrence Greedy Pattern
Single Number: XOR Cancellation Pattern
Power of Two: n and n-1 Pattern
Number of 1 Bits: Brian Kernighan Pattern
Single Number III: Rightmost Set Bit Pattern
XOR From 1 to N: Modulo Cycle Pattern
Prime Check: Square Root Trial Division Pattern
Sieve of Eratosthenes: Prime Marking Pattern
GCD: Euclidean Remainder Pattern
Binary Exponentiation: Fast Power Pattern
Modular Inverse: Extended Euclid Pattern
Implement Trie: Prefix Tree Pattern
Longest Common Prefix: Single Branch Trie Pattern
LRU Cache: Hash Map Plus Recency List Pattern
Segment Tree: Range Sum Query Pattern
Fenwick Tree: Binary Indexed Prefix Sum Pattern
CONTENTS

Remove Nth Node From End: Two pointers Pattern

Use a fixed gap between fast and slow pointers to remove the nth node from the end in one pass.

DSA Course: Interview Patterns and Problem Solving
Module 5: Linked List
dsa
data structures and algorithms
+4
May 28, 2026
30
A

Learning Outcome

After this lesson, you should be able to remove a node from the end of a linked list using a one-pass pointer gap and a dummy node.

Problem Statement

Given the head of a linked list and an integer n, remove the nth node from the end of the list and return the head.

InputnOutput
1 -> 2 -> 3 -> 4 -> 521 -> 2 -> 3 -> 5
11null

Brute Force Approach

Count the length of the list, compute which node should be removed from the front, then walk again to unlink it.

This is correct, but it requires two passes.

Optimized Approach

Create a dummy node before the head. Move fast ahead by n + 1 steps from the dummy. Then move fast and slow together until fast reaches null. At that moment, slow.next is the node to remove.

Exact Pseudocode

dummy = new node before head
dummy.next = head
fast = dummy
slow = dummy
for step from 0 to n:
  fast = fast.next
while fast is not null:
  fast = fast.next
  slow = slow.next
slow.next = slow.next.next
return dummy.next

Reference Code

class Solution:
    def removeNthFromEnd(self, head, n):
        dummy = ListNode(0)
        dummy.next = head
        slow = dummy
        fast = dummy

        for _ in range(n + 1):
            fast = fast.next

        while fast:
            slow = slow.next
            fast = fast.next

        slow.next = slow.next.next
        return dummy.next

Sample Dry Run

PhasefastslowMeaning
Start at dummydummydummyDummy protects head removal
Move fast n+1 steps3dummyGap is set for n = 2
Move together4 then 5 then null1 then 2 then 3Slow stops before node 4
Removenull3Set 3.next = 5

Complexity

MeasureValueReason
TimeO(n)The list is traversed once after setting the gap.
SpaceO(1)Only pointers and one dummy node are used.

Edge Cases

  • Removing the head node.
  • Single-node list.
  • Removing the tail node.

Interview Checklist

  • Use a dummy node to handle removing the head.
  • Create a gap of n + 1 from dummy to fast.
  • Stop slow on the node before the one to remove.

FAQs

Why use a dummy node?

It makes head removal follow the same unlinking logic as every other removal.

Why move fast n + 1 steps?

That positions slow one node before the target when fast reaches the end.

What is the core pattern?

Two pointers with a fixed gap.

Share this article

Share on TwitterShare on LinkedInShare on FacebookShare on WhatsAppShare on Email

Test your knowledge

Take a quick quiz based on this chapter.

mediumDSA Course
Remove Nth Node From End - Two pointers Pattern Practice Quiz
5 questions8 min

0 comments

Please login to comment.
No comments yet.
Lesson 5 of 5 in Module 5: Linked List
Previous in Module 5: Linked List
Middle of the Linked List: Fast and slow pointers Pattern
Next section: Module 6: Trees
Binary Tree Traversals: DFS recursion Pattern
Module 6: Trees
Back to DSA Course: Interview Patterns and Problem Solving
Back to moduleCategories